Creating image sections using imcopy within script

smp wrote on Oct 21, 2008

hi,
I want to do following:
In following segment of a procedure script,
newfile1 is a file which contains 5 image names.
newfile2 is a file which will contain image section [1:1084,*] of each of 5 images from file newfile1.
I am using imcopy task for this.
But I get the error :
Can't open file
if I do following:

           :
           :
           :
 for(n=1;n<=5;n=n+1)
   {
     printf("left_%d.fits\n", n ,  >> newfile2)          # creating new image names
   }

imcopy(input="@"//newfile1//"[1:1084,*]", output="@"//newfile2, v-)  # divide image into 2 halves 
          :

And I get following error:
Number of output and input images not same
if do the following:

           :
           :
           :
 for(n=1;n<=5;n=n+1)
   {
     printf("left_%d.fits\n", n ,  >> newfile2)          # creating new image names
   }

imcopy(input=newfile1//"[1:1084,*]", output="@"//newfile2, v-)  # divide image into 2 halves 
           :

please help.

regards

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Francisco Valdes wrote on Oct 21, 2008

It seems to me you have the files backward, your input should be "@"//newfile2 and your output should "@"//newfile1. (The second error is because you don't have the "@" for the input file). What you want to have for an imcopy after expanding the names and @files is

imcopy abc[1:1084,*] newabc

In other words, the input has the image section but the output does not. The only time you use an image section on output is when copying into a section of an existing image in which case the sizes of the input and output must match.

Yours,
Frank Valdes

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Last post on Oct 21, 2008